Fujitsu Interview Pattern / Experience

The process took a week for me and then I was considered for the interview which comprised of four rounds.

First Round: Telephonic Interview
The interview lasted for about thirty minutes and began with the basic questions about myself.Then she started asking me about some technical questions revolving around embedded systems and some basic c/c++ questions

Second Round: Written Test
The written test consisted of just the technical questions. There were 10 questions and 45 minutes were assigned to complete all of them. I won't say that the test was easy as a couple of questions were time taking but I was able to complete the test in the given time.

Third Round: HR Interview
The HR was really easy going and I enjoyed this interview thororughly. I was asked some logical reasoning questions in the beginning and then the entire focus shifted to c++ and java related questions only to be followed by questions regarding my past experience. You won't feel any burden or pressure given that you are interviewed by the same person.

Fourth Round: Technical Round
This is the round that you might want to prepare for. It was quite challenging. The questions asked regarding programming and technical language were really difficult and all the easy time I had in the previous interview was covered up perfectly in this round.

#Preparation :

#Fujitsu_Interview_Puzzle:-

Q1. You have two strings whose only known property is that when you light one end of either string it takes exactly one hour to burn. The rate at which the strings will burn is completely random and each string is different.

How do you measure 45 minutes?

ANS:

Light both the ends of the first string and one end of the second string. 30 minutes will have passed when the first string is fully burned, which means 30 minutes have burned off the second string. Light the end of the second string and when it is fully burned, 45 minutes will have passed.

Q2. How many people must be gathered together in a room, before you can be certain that there is a greater than 50/50 chance that at least two of them have the same birthday?

ANS:

Only twenty-three people need be in the room, a surprisingly small number. The probability that there will not be two matching birthdays is then, ignoring leap years, 365x364x363x...x343/365 over 23 which is approximately 0.493. This is less than half, and therefore the probability that a pair occurs is greater than 50-50. With as few as fourteen people in the room the chances are better than 50-50 that a pair will have birthdays on the same day or on consecutive days.

Q3. On Bagshot Island, there is an airport. The airport is the home-base of an unlimited number of identical airplanes. Each airplane has a fuel capacity to allow it to fly exactly 1/2 way around the world, along a great circle. The planes have the ability to refuel in flight without loss of speed or spillage of fuel. Though the fuel is unlimited, the island is the only source of fuel.

What is the fewest number of aircraft necessary to get one plane all the way around the world assuming that all of the aircraft must return safely to the airport? How did you get to your answer?

Notes:
(a) Each airplane must depart and return to the same airport, and that is the only airport they can land and refuel on ground.
(b) Each airplane must have enough fuel to return to airport.
(c) The time and fuel consumption of refueling can be ignored. (so we can also assume that one airplane can refuel more than one airplanes in air at the same time.)
(d) The amount of fuel airplanes carrying can be zero as long as the other airplane is refueling these airplanes. What is the fewest number of airplanes and number of tanks of fuel needed to accomplish this work? (we only need airplane to go around the world)

ANS:

As per the puzzle given above The fewest number of aircraft is 3! Imagine 3 aircraft (A, B and C). A is going to fly round the world. All three aircraft start at the same time in the same direction. After 1/6 of the circumference, B passes 1/3 of its fuel to C and returns home, where it is refueled and starts immediately again to follow A and C.

C continues to fly alongside A until they are 1/4 of the distance around the world. At this point C completely fills the tank of A which is now able to fly to a point 3/4 of the way around the world. C has now only 1/3 of its full fuel capacity left, not enough to get back to the home base. But the first auxiliary aircraft reaches it in time in order to refuel it, and both auxiliary aircraft are the able to return safely to the home base.

Now in the same manner as before both B and C fully refueled fly towards A. Again B refuels C and returns home to be refueled. C reaches A at the point where it has flown 3/4 around the world. All 3 aircraft can safely return to the home base, if the refueled process is applied analogously as for the first phase of the flight.

Q4. You are standing on the verge of making a fortune. You have fifty precious stones and fifty non-precious stones. You are provided with two bags labelled as Heads and Tails respectively. What you have to do is distribute the stones in these two bags. After that a coin will be flipped and what comes (heads or tails) will decide you will pick up a stone randomly from which bag.

How will you be distributing the stones so that you maximize the probability of picking up a precious stone? If you pick it, all precious stones will be yours.

ANS:

You can put one precious stone in any one of the bag and all the rest in the other bag. If you do it, you will get just a shade under 3/4 probability of picking up a precious stone.

Q5. I have two sand hour glasses:
1. A 7 minute one and
2. An 11 minute one.

Using just these 2 sand hour glasses, how can I measure time as 15 minutes?

ANS:

1. Start both the 7 minute hour glass & 11 minute hour glass.
2. Wait till the 7 minute hour glass times out. Time is 7 minute!
3. Restart the 7 minute hour glass. At this time 11 minute hour glass will have 4 minutes left to time out.
4. As soon as 11 minute glass times out invert the 7 minute hour glass. Total time now is 11 minutes.
5. After inverting 7 minute hour glass, it will now have 4 minutes left for time out.
6. After these 4 minutes times out, the total time is 15 minutes.

#Fujitsu_Interview_Questions

Fujitsu Interview Questions:-

Q1. Name some translator and compile options and explain their meaning.

Q2. How to create zone users?

Q3. How to import mass transport request? Explain the procedure and draw backs.

Q4. How can you do kernal upgrade in dual stack?

Q5. How many rows will return from dual table?

Q6. What is System tuning? What are the activities involved in system tuning?

Q7. What are the error tables in OM?

Q8. What are principles of good testing scripts for automation?

Q9. What is the purpose of web dispatcher? How to install and configure Web Dispatcher? What are the prerequisites?

Q10. What is difference between checked and unchecked exception?

Q11. Can we call a procedure into another procedure? If yes means how you can pass the parameters for the two procedures?

Q12. What is Transport Group & Transport directory in STMS?

Q13. In case only Gateway server goes down, then what is the impact in existing on new users trying to login the Siebel application?

Q14. Why we use one step and two step in STO?

Q15. How many types of projects are there in project module?

Q16. Why is bdc _cursor and GET_Cursor used?

Q17. What is check pending option?

Q18. How to write personnel calculation rules in payroll schema?

Q19. What are the types of universes? What is the difference between metri universe and simple universe? In what context we use metric universe?

Q20. How can you handle run time exceptions in Java?

All the Best.

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Helping Hands 7

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